The breakdown of glucose in a cell yields pyruvate in the:
Correct answer: C. Presence or absence of oxygen
- A. Presence of oxygen
- B. Absence of oxygen
- C. Presence or absence of oxygen
- D. High concentration of oxygen
Explanation
The correct answer is option C: presence or absence of oxygen. Glycolysis is the initial process in glucose metabolism, converting glucose into pyruvate within the cytoplasm, regardless of oxygen presence. It is considered an anaerobic process since it doesn't require oxygen. Under aerobic conditions, pyruvate is further oxidized in the mitochondria, while under anaerobic conditions, it is converted into lactic acid or ethanol. Options A and B are incorrect, as they each consider only one condition, while option D is incorrect, as glycolysis is not affected by oxygen concentration.
Last updated