The amount (in litres) of Oxygen at STP that is required for the combustion of 4gm of ethylene is:
Correct answer: B. 9.6 litres
- A. 96 litres
- B. 9.6 litres
- C. 44.8 litres
- D. 67.2 litres
Explanation
4gm of Ethylene (C2H4) = 0.1428 moles or 3.2L of it. The Balanced Chemical Equation for this reaction is: C2H4+ 3O2 -> 2CO2 + 2H2O+ energy So, if one mole of Ethylene requires 3 moles of oxygen to burn completely then, 3.2L of Ethylene requires 9.6L of oxygen for complete combustion. (Avagadro's law n (moles) are directly proportional to V (volume). Hence, all other options are rendered as incorrect.
This question appeared on the HEC Phase I 2017 paper, which you can sit online with every answer explained.
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About Alkenes
Alkenes are unsaturated hydrocarbons containing a carbon-carbon double bond with sigma and pi components and restricted rotation. Their reactions include electrophilic addition of hydrogen, halogens, hydrogen halides and water, with Markovnikov orientation, oxidation, combustion and polymerisation, while their preparation commonly involves elimination from alkyl halides or alcohols.
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