The adjacent figure shows the force-displacement graph of a moving body, the work done in displacing the body from x=0 to x=35m is equal to:
Correct answer: C. 287.5 J
- A. 25 J
- B. 200 J
- C. 287.5 J
- D. 50 J
Explanation
Work done = Area of triangle (0 to 10s)+Area of rectangle (10 to 30s)+Area of trapezium(30 to 35s)W=( 1/2×10×10)+(20×10)+(1/2) × (10+5)×5)W= 287.5J
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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