Due to application of 5 N force an object moves 10 meter along perpendicular direction of the force. What amount work is done?
Correct answer: D. 0 J
- A. 50 J
- B. 5 J
- C. 15 J
- D. 0 J
Explanation
The explanation of this question is: Work is a scalar quantity that can be represented as a dot product of 2 vector quantities force and displacement. Or W = fd cos θ where θ = Angle between force and displacement When force and displacement are perpendicular, then θ = 90o and cos 90o = 0 so W = fd x 0 = 0
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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