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Study the following facts:Zn → Zn+2 + 2e― Eo = +0.76 VCu → Cu+2 + 2e― Eo = - 0.34 V

Correct answer: C. Cu+2 + Zn → Cu + Zn+2

  • A. Cu + Zn+2 → Cu+2 + Zn
  • B. Cu+2 + Zn+2 → Cu + Zn
  • C. Cu+2 + Zn → Cu + Zn+2
  • D. Cu+2 + Zn+2 → Cu + Zn+2

Explanation

The half cell equation with the lower Eo is the anode. Electrons travel from cathode to anode. (Flip the equation with the lower Eo and then 2e cancel out).the correct redox reaction involving Cu and Zn is: Cu+2 + Zn -> Cu + Zn+2Cu+2 + Zn -> Cu + Zn+2: This equation represents a redox reaction between copper ions (Cu2+) metal (Zn). In this reaction, copper ions gain two electrons to form copper metal, while zinc atoms two electrons to form zinc ions. This reaction is a spontaneous redox reaction because the potential of copper ions (Cu2+) is lower than that of zinc ions (Zn2+). Therefore, copper ions reduced, and zinc metal is oxidized.

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