Six consecutive integers are given. The sum of the first three is 27.What is the sum of the last three?
Correct answer: D. 36
- A. 29
- B. 30
- C. 32
- D. 36
Explanation
Using the number sequence formula a number sequence can be written down for the six consecutive integers; N being the first integer N,N+1,N+2,N+3,N+4,N+5 If the sum of the first three integers = 27 I.e N+N+1+N+2 = 27 3N+3 = 27 3N = 27-3 = 24 N = 24/3 = 8 N = 8 For the sum of last three integers, the formula is; N+3+N+4+N+5 N = 8 i.e. 8 + 3 + 8 + 4 + 8 + 5 = 36
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