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Ring structure of glucose is due to the formation of hemiacetal and ring formation between:

Correct answer: A. C1 and C5

  • A. C1 and C5
  • B. C1 and C4
  • C. C1 and C3
  • D. C3 and C4

Explanation

The ring structure of glucose is due to the formation of a hemiacetal between the aldehyde group at carbon 1 and the hydroxyl group at carbon 5. This reaction results in the formation of a six-membered ring called a pyranose. The hemiacetal formation is a reversible process, and the ring can open up again to form an aldehyde and an alcohol.

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About Macromolecules

Proteins are classified by shape, composition and structure, from primary amino acid sequence to secondary, tertiary and quaternary organisation, and their biological roles are linked to this structure. Enzymes are examined as protein biocatalysts, including active sites, substrate specificity, activation energy, cofactors and factors affecting activity.

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