Ring structure of glucose is due to the formation of hemiacetal and ring formation between:
Correct answer: A. C1 and C5
- A. C1 and C5
- B. C1 and C4
- C. C1 and C3
- D. C3 and C4
Explanation
The ring structure of glucose is due to the formation of a hemiacetal between the aldehyde group at carbon 1 and the hydroxyl group at carbon 5. This reaction results in the formation of a six-membered ring called a pyranose. The hemiacetal formation is a reversible process, and the ring can open up again to form an aldehyde and an alcohol.
Last updated
About Macromolecules
Proteins are classified by shape, composition and structure, from primary amino acid sequence to secondary, tertiary and quaternary organisation, and their biological roles are linked to this structure. Enzymes are examined as protein biocatalysts, including active sites, substrate specificity, activation energy, cofactors and factors affecting activity.
Practise Macromolecules
299 free Macromolecules MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1 calorie = _ Joules.
A carbohydrate that cannot be acid hydrolyzed is called a:
A chemist isolated a protein from a crab and wanted to determine its molecular weight. Which of the following method would have given the best result for him?
A dipolar charged but overall electrically neutral ion is called:
A disease caused by Plasmodium parasite is: