Ratio of average power to the peak power in resistive AC circuit is?
Correct answer: A. 1:2
- A. 1:2
- B. 2:1
- C. 1:1
- D. none
Explanation
In a resistive AC circuit, the voltage and current are sinusoidal and in phase. The average power (Pavg) in such a circuit can be calculated using the formula Pavg = (1/2)Ppeak, where Ppeak is the peak power. This is because the average value of a sine wave over a complete cycle is zero, but since power is proportional to the square of the sine (which is always positive), the average power is half of the peak power. Therefore, the ratio of average power to peak power is 1:2. This explains why Option A is correct, while Options B, C, and D are incorrect as they do not represent the correct relationship between average and peak power in a sinusoidal AC circuit.
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About Alternating Current
Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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