Asked in ETEA MDCAT 2017 2017Moderate

Propene reacts with hypochlorous acid to form

Correct answer: B. CH3-CH-CH2Cl ⋮ OH

  • A. CH3-CH-CH2O ⋮ ClOHCl
  • B. CH3-CH-CH2Cl ⋮ OH
  • C. CH3-CH2-CH2Cl ⋮ OH
  • D. CH3-CH-CH2 ⋮ OH

Explanation

The reaction between propene and hypochlorous acid (HOCl) can be represented as follows:CH3CH=CH2 + HOCl → CH3CH(OH)CH2ClThe product formed is 2-chloropropan-1-ol (CH3CH(OH)CH2Cl), which has a hydroxyl (-OH) group attached to the carbon adjacent to the chlorine atom. Therefore, the correct answer is option B) CH3-CH-CH2CI: OH.

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About Alkenes

Alkenes are unsaturated hydrocarbons containing a carbon-carbon double bond with sigma and pi components and restricted rotation. Their reactions include electrophilic addition of hydrogen, halogens, hydrogen halides and water, with Markovnikov orientation, oxidation, combustion and polymerisation, while their preparation commonly involves elimination from alkyl halides or alcohols.

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