Point out the shape and bond angles present in Boron trifluoride:

Correct answer: C. Trigonal planar, 120 degree.

  • A. Triangular pyramidal , 107 degree.
  • B. Tetrahedral,104.5 degree.
  • C. Trigonal planar, 120 degree.
  • D. None of these.

Explanation

Boron trifluoride (BF3) has a trigonal planar molecular geometry with bond angles of 120 degrees.In BF3, the central boron (B) atom is surrounded by three fluorine (F) atoms. The boron atom has an incomplete octet (only six electrons in its valence shell), making it an exception to the octet rule. To achieve stability, boron forms three sigma bonds with three fluorine atoms. The molecule's shape is trigonal planar, with the three fluorine atoms situated symmetrically around the central boron atom.

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Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.

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