Organ pipe "Y" (open at both ends) is half as long as organ pipe "X" (open at One end as shown. The ratio of their fundamental frequencies fx:fv is:
Correct answer: D. 1:4
- A. 1:1
- B. 2:1
- C. 1:2
- D. 1:4
Explanation
An organ pipe open at both ends (Pipe Y) has a fundamental frequency given by f = v/(2L), where v is the speed of sound and L is the length of the pipe. An organ pipe open at one end and closed at the other (Pipe X) has a fundamental frequency given by f = v/(4L). Since Pipe Y is half the length of Pipe X, its fundamental frequency is twice the fundamental frequency of an open-open pipe of the same length. Thus, the fundamental frequency of Pipe Y is four times that of Pipe X. Therefore, the ratio of their fundamental frequencies fx:fy is 1:4. The other options do not account for the differences in pipe lengths and end conditions appropriately, hence they are incorrect.
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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