A stretched string is 4m long and it has 4 loops of stationary waves, then the wavelength is:
Correct answer: C. 2 m
- A. 1 m
- B. 3 m
- C. 2 m
- D. 4 m
Explanation
The length of the string is 4 m, and it supports 4 complete loops of stationary waves. Each loop corresponds to half a wavelength. Therefore, the wavelength λ can be calculated by dividing the total length of the string (4 m) by the number of loops, resulting in a loop length of 1 m. Since a full wavelength consists of two loops, the wavelength is 2 m. Thus, Option C is correct. Options A, B, and D are incorrect because they do not result in an integer number of loops consistent with the string length.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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