One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s. The maximum height reached by the first object will be that of the other:
Correct answer: C. 100 times
- A. 10 times
- B. 1000 times
- C. 100 times
- D. 10000 times
Explanation
To determine the maximum height reached by each object, we use the formula for the maximum height in projectile motion: h = v2/2g. Here, v is the initial velocity, and g is the acceleration due to gravity, which is approximately 10 m/s2 for simplicity.For the first object with an initial velocity of 100 m/s: h1 = 1002/[2(10)] = 10000/20 = 500 m.For the second object with an initial velocity of 10 m/s: h2 = 102/[2(10)] = 100/20 = 5 m.Thus, the maximum height reached by the first object is 500/5 = 100 times that of the second object.Options A, B, and D are incorrect because they do not match the calculated factor of 100 times, which is the result derived from the formula.
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