A force of 10N acts on a body of mass 20kg for 10 seconds. The change in its momentum is
Correct answer: B. 100 kg⋅m/s
- A. 50 kg⋅m/s
- B. 100 kg⋅m/s
- C. 300 kg⋅m/s
- D. 1000 kg⋅m/s
Explanation
Step 1: Acceleration calculation Applying Newton's second law ∑F=ma ⇒F=ma ⇒10(N)=20(kg) a ⇒a=0.5m/s2 Step 2: Final speed Since acceleration is constant, ∴ Applying equation of motion v=u+at u= Initial speed =0 v= Final speed v=0+0.5(m/s2)×10(s) =5m/s Step 3: Change in momentum ΔP ΔP=m(v−u) =20(5−0)kgm/s =100kgm/s Hence option B is correct. numerical type question so only one answer is possible
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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