One mole of glucose was dissolved in 1 kg of water, ethanol, ether, and benzene separately and the molal boiling point constant of each solution was found to be 0.52, 1.75,2.16, and 2.70 in the units of / °C kg mol-1 respectively. Which of the following figures shows benzene as a solvent in solution?
Correct answer: D. 4
- A. 1
- B. 2
- C. 3
- D. 4
Explanation
Since the solution of benzene and glucose has the highest molal boiling point constant of 2.70, this means that the equilibrium between benzene vapor and the solution will be shifted toward the solution side. Hence vapor pressure of Benzene will be the lowest and the level of mercury will be the highest. As it is numerical, it can have only one possible answer.
Last updated
About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
Practise Chemical Equilibrium
625 free Chemical Equilibrium MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1.8 x 10 -5 is the dissociation constant of:
1 mole of CH3COOH and 1 mole of C2H5OH react to produce 2/3 mole of CH3COOC2H5. The equilibrium constant is
1 mole of ethyl alcohol was treated with one mole of acetic acid at 25°C. 2/3 of the acid changes into ester at equilibrium. The equilibrium constant of the reaction will be:
2HF ⇌ H2 + F2 PCI5 ⇌ PCI3 + Cl2The statement that is false about the Ke of both the reactions is;
2O3 ⇌ 3O2 Ke = 1055 at 25°C, it explains