Students were heating CaCO3 in an open container to produce CO2 gas,CaCO3(s) ⟶ CaO(s) + CO2(g)If we increase pressure on this system the:
Correct answer: D. System does not obey equilibrium rules
- A. Equilibrium will shift towards right
- B. Equilibrium will shift towards left
- C. Equilibrium will not be disturbed
- D. System does not obey equilibrium rules
Explanation
The correct answer is that the system does not obey equilibrium rules. Chemical equilibrium can only be established in a closed system where reactants and products are contained. In this scenario, the CaCO3 is heated in an open container, allowing the CO2 gas to escape. As a result, the system cannot reach equilibrium, as the continuous loss of CO2 gas prevents the establishment of a dynamic balance between reactants and products.All other options are incorrect because they assume that equilibrium can be achieved or disturbed in an open system, which is not possible. The nature of an open system prevents the maintenance of chemical equilibrium as it allows mass to be lost to the surroundings.
Last updated
About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
Practise Chemical Equilibrium
625 free Chemical Equilibrium MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1.8 x 10 -5 is the dissociation constant of:
1 mole of CH3COOH and 1 mole of C2H5OH react to produce 2/3 mole of CH3COOC2H5. The equilibrium constant is
1 mole of ethyl alcohol was treated with one mole of acetic acid at 25°C. 2/3 of the acid changes into ester at equilibrium. The equilibrium constant of the reaction will be:
2HF ⇌ H2 + F2 PCI5 ⇌ PCI3 + Cl2The statement that is false about the Ke of both the reactions is;
2O3 ⇌ 3O2 Ke = 1055 at 25°C, it explains