1 mole of ethyl alcohol was treated with one mole of acetic acid at 25°C. 2/3 of the acid changes into ester at equilibrium. The equilibrium constant of the reaction will be:
Correct answer: D. 4
- A. 1
- B. 2
- C. 3
- D. 4
Explanation
The reaction proceeds as follows:CH 3COOH +C2 H5OH ⇌ CH3COOC2H5 + H2OThe Kc calculation is shown in the image below:
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