One end of the cylindrical pipe has a radius of 1.5cm. If water streams (density=1.0x10³kg/m3 ) steadily out of it at 7.0m/s, the volume rate is:
Correct answer: A. 4.95×10⁻³ m³/s
- A. 4.95×10⁻³ m³/s
- B. 4.9 m3/s
- C. 7.0 m³/s
- D. 49 m³/s
Explanation
Volumetric flow Q = A v = π r² v. With r = 0.015 m: A = π(0.015) ² ≈ 7.07×10⁻⁴ m². Q = 7.07×10⁻⁴×7 ≈ 4.95×10⁻³ m³/s ≈ 4.9×10⁻³ m³/s.
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