An incompressible liquid flows along the pipe with the area of cross-section A₁ and A₂ with velocities V₁ and V₂ respectively. The ratio of the speeds V₁/V₂ is:
Correct answer: B. A₂/A₁
- A. A₁/A₂
- B. A₂/A₁
- C. √A₁/A₂
- D. √A₂/A₁
Explanation
Continuity for incompressible flow gives A₁V₁ = A₂V₂ ⇒ V₂/V₁= A₁ /A₂ . Thus the speeds are inversely proportional to thecross-sectional areas.
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