on moving a charge of 20 coulombs by 2 cm, 2j of work is done then the potential difference between the point is
Correct answer: A. 0.1v
- A. 0.1v
- B. 8v
- C. 2v
- D. 0.5v
Explanation
We can solve this problem using the formula for potential difference:Potential difference (V) = Work done (W) / Charge (Q)Given information:Work done (W) = 2 JCharge (Q) = 20 CCalculation:V = W / Q = 2 J / 20 C = 0.1 VTherefore, the potential difference between the points is a. 0.1 V
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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