A parallel plate condenser with oil between the plates (dielectric constant of oil k =2) has a capacitance of C. If the oil is removed then the capacitance of the capacitor becomes:
Correct answer: D. C/2
- A. √2 C
- B. 2 C
- C. c/√2
- D. C/2
Explanation
The capacitance of a parallel plate capacitor with a dielectric material between the plates is given by the formula:C= k. ε0. A/dk is the relative permittivity (dielectric constant) of the material between the platesε0 is the vacuum permittivity.A is the area of the plates.d is the separation between the plates.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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