Moderate

MgO is used in making of the lining of Watt furnaces. It is extracted from seawater as follows. Aqueous calcium hydroxide is added to seawater:Ca(OH)(aq) MgCl2(aq) → Mg(OH)2(s) + CaCl2 (aq)Mg(OH)2 is then filtered off and roasted. Which of the following comparisons of calcium and magnesium explains why Mg(OH)2 is formed?

Correct answer: D. The solubility product of Mg(OH)2 is lower than that of Ca(OH)2

  • A. Mg is less electropositive than calcium
  • B. Mg is lower then Ca in the relative reactivity series
  • C. The chance of hydration of Mg 2+ is less exothermic than of Ca2+
  • D. The solubility product of Mg(OH)2 is lower than that of Ca(OH)2

Explanation

The solubility product (Ksp) is a measure of the equilibrium solubility of a compound in water. It is determined by the concentrations of the ions in the solution. A lower solubility product indicates lower solubility, meaning the compound is less soluble in water.In the reaction described, when calcium hydroxide (Ca(OH)2) is added to seawater containing magnesium chloride (MgCl2), a precipitation reaction occurs. The lower solubility product of Mg(OH)2 compared to Ca(OH)2 results in the formation of solid Mg(OH)2, which appears as a precipitate and can be filtered off. Therefore, option d is correct.

Last updated

About s-Block and p-Block Elements

The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.

Practise s-Block and p-Block Elements

1,359 free s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Chemistry questions like this

Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions