Maximum number of molecules will be in:
Correct answer: C. 10 g of H2
- A. 1 g of H2
- B. 22 g of O2
- C. 10 g of H2
- D. 44 g of CO2
Explanation
Option C: molecular mass of H2 = 2 mass of H2 given = 10 g no of moles in 10 g of H2 : 10 / 2 = 5 mol no of molecules in 1 mole = 6.02 x 1023 no of molecules in 5 moles : 5 x 6.02 x 1023 = 3.01 x 1024 According to the calculations, 10 g of H2 contains the most molecules.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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