How many water molecules will be lost on dehydrating 0.684 g of sucrose?
Correct answer: A. 1.3244 x 10^22
- A. 1.3244 x 10^22
- B. 6.02 x 10^20
- C. 6.622 x 10^21
- D. 7.224 x 10^21
Explanation
Ratio of Sucrose : Water in dehydration reaction is = 1 : 11molecular mass of sucrose C12H22O11: (12 x 12) + (1 x 22) + (16 x 11) = 342mass of sucrose given = 0.684 gmoles of sucrose: 0.684 / 342 = 0.002moles of H2O obtained = 11 x 0.002 = 0.022molecules in 1 mol of H2O = 6.02 x 1023molecules in 0.022 mol of H2O = 0.022 x 6.02 x 1023 = 1.3244 x 1022
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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