In the reaction 3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O. What is the equivalent weight of HNO₃? (If the molecular weight of HNO₃ is M).

Correct answer: D. 4/3 M

  • A. M
  • B. M/3
  • C. 3/4 M
  • D. 4/3 M

Explanation

The n-factor for HNO₃ in the overall reaction is the total electrons transferred (6) divided by the moles of HNO₃ used (8), which equals 3/4. The equivalent weight is Molecular Weight / n-factor = M / (3/4) = 4M/3

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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.

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