100g of CaCO, is treated with 1 liter of 1 NHCI. What would be the weight of CO2 liberated after the completion of the reaction
Correct answer: C. 22g
- A. 5.5g
- B. 11g
- C. 22g
- D. 33g
Explanation
Let's perform the calculations:Molar mass of CACO3=40.08+12.01+(3×16.00)Moles of CaCO3 =100/40.08+12.01+(3×16.00)Moles of CO2 =Moles of CaCO3 Weight of CO2 =Moles of CO2 ×(12.01+(2×16.00))After performing the calculations, the weight of CO2 is approximately 22g.Therefore, the correct answer is: c. 22g
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