100g of CaCO, is treated with 1 liter of 1 NHCI. What would be the weight of CO2 liberated after the completion of the reaction
Correct answer: C. 22g
- A. 5.5g
- B. 11g
- C. 22g
- D. 33g
Explanation
Let's perform the calculations:Molar mass of CACO3=40.08+12.01+(3×16.00)Moles of CaCO3 =100/40.08+12.01+(3×16.00)Moles of CO2 =Moles of CaCO3 Weight of CO2 =Moles of CO2 ×(12.01+(2×16.00))After performing the calculations, the weight of CO2 is approximately 22g.Therefore, the correct answer is: c. 22g
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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