In the following reaction sequence, product D will be:

Explanation

The above reaction scheme describes dehydrohalogenation of the alkyl halide into an alkene, followed by hydration of the alkene. The first step involves the reaction of propyl bromide with alcoholic KOH, which will result in elimination or dehydrohalogenation, whereby the halogen atom and adjacent carbon atom's hydrogen atom is removed, resulting in the formation of a double bond between the two carbons, forming propane, which is product C. Propene is acted upon by aqueous H2SO4, which implies hydration or addition of H2O, resulting in the formation of two products; the major product which is 2-propanol and the minor product which is 1-propanol so, the major product is the preferred option, i.e. option C.