In the balanced chemical reaction, IO3- + aI- + bH+→ cH2O + dI2 a, b, c and d respectively correspond to:
Correct answer: A. 5, 6, 3, 3
- A. 5, 6, 3, 3
- B. 5, 3, 6, 3
- C. 3, 5, 3, 6
- D. 5, 6, 5, 5
Explanation
Following is the solution to this question:
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrochemistry
Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
Practise Electrochemistry
699 free Electrochemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrochemistry questions
In an experiment, 50 ml of 0.1M solution of a salt reacted with 25 ml of 0.1M solution of Sodium sulfite. The half equation for the oxidation of sulfite ion is: SO32-(Aq) H2O→ SO42- + 2H+ + 2e- If the oxidation number of the metal in the salt was 3, what would be the new oxidation number of the metal?
Electric current in solutions is carried by:
What change in oxidation number of Cu takes place in the following reaction: Cu+4HNO3 →Cu(NO3 )2 +2NO2 +2H2 O
Oxidation state of 'V' in Rb4Na[HV10O28] is:
In which of the following reaction(s) does H2SO4 act as an oxidizing agent and as an acid?
In a reaction, 3 moles of electrons are gained by 1 mole of HNO3. Assuming no change in the oxidation number of hydrogen and oxygen, the possible product obtained due to reduction will be: