In sodium sulphate (Na2SO4) what is the oxidation number of sulphur?
Correct answer: C. +6
- A. +2
- B. +4
- C. +6
- D. +8
Explanation
The oxidation number of sulfur in sodium sulfate (Na2SO4) is +6. Oxidation state is a number assigned to an atom in a chemical compound that represents the number of electrons lost or gained, if the number is negative) by an atom when it forms a chemical bond with another atom.
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Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
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