In laminar flow through a round tube, the discharge varies ______________________?
Correct answer: B. Inversely as the viscosity
- A. Linearly as the viscosity
- B. Inversely as the viscosity
- C. Inversely as the pressure drop
- D. As the square of the radius
Explanation
For laminar flow in a round tube, the Hagen–Poiseuille equation gives Q = πR⁴ΔP/(8μL), so discharge is inversely proportional to viscosity. It is also proportional to pressure drop and the fourth power of radius, not the square.
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