In a stationary wave the distance between consecutive antinodes is 25cm. If the wave velocity is 300ms-1, then the frequency of the wave will be:
Correct answer: C. 600 Hz
- A. 150 Hz
- B. 300 Hz
- C. 600 Hz
- D. 750 Hz
Explanation
Distance between two consecutive antinodes is half the wavelength. We know that f=V/wavelength so 300/0.5 equals to 600.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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