A tuning fork A produces 4 beats / second with another turning fork B of frequency 280 Hz. When fork A is loaded with a little wax, the beat frequency changes to 2. The frequency of fork A before loading is:
Correct answer: B. 284 Hz
- A. 292 Hz
- B. 284 Hz
- C. 290 Hz
- D. 288 Hz
Explanation
Beat frequency is given by the equation; Beat frequency = f1-f2Whereas f1 is AAnd f2 is BSince the frequency of the B tuning fork is 280 Hz and the number of beats per second before applying wax is 4. Therefore,4-f1-280 F1-4+280 F1/A is 284Hz.As it is a numerical, it can have only one possible answer.
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