In a stationary wave, if the string is made to vibrate in n loops, the frequency of stationary waves set up on the string will be:
Correct answer: A. fn = n * fl
- A. fn = n * fl
- B. fn = n + fl
- C. fn =fl/ n
- D. n * fn = fl
Explanation
The correct relationship between the number of loops (n) in a vibrating spring and the frequency (f) of the stationary waves set up on the string is:fn = n × fiHere, fn represents the frequency of the stationary waves, n is the number of loops in the vibrating spring, and fi is the fundamental frequency, or the lowest possible frequency, of the vibrating spring.This relationship indicates that the frequency of the stationary waves is directly proportional to the number of loops in the vibrating spring. As the number of loops increases, the frequency of the stationary waves also increases proportionally.Therefore, the correct answer is "fn = nfi," which represents the relationship between the number of loops and the frequency of the stationary waves on the string.
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About Stationary Waves
Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.
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