Asked in MDCAT Free Mock 2024 2024Moderate

An air pipe opens at both ends. A stationary wave is produced in the second harmonic mode. What is the phase difference between the motion of the particles at the end of the pipe and at the center of the pipe?

Correct answer: C. 180 DEG

  • A. 0 DEG
  • B. 90 DEG
  • C. 180 DEG
  • D. 270 DEG

Explanation

Option C is correct since the formula becomes L=lambda, where L is the length of the tube. Since the stationary wave produced is in the second harmonic mode, the particles at the edge of the tube and in the middle will both be at antinodes. The distance between two consecutive antinodes equals half a wavelength which corresponds to a phase difference of 180 degrees.Option A is incorrect since the phase difference of 0 degrees represents that both particles are at the same position.Option B is incorrect since a phase difference of 90 degrees represents that the particles are at a distance equal to a quarter wavelength.Option D is incorrect since a phase difference of 270 degrees represents that the particles are at a distance equal to 3 quarters of a wavelength.

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About Stationary Waves

Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.

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