In a practical examination, a student has been given a task to find the specific heat of 0.5 kg of water placed at a burning burner where thermal energy of 1000 J is used to raise its temperature from 80oC to 90oC.The specific heat of water will be
Correct answer: A. 200 J/kgoC.
- A. 200 J/kgoC.
- B. 100 J/kgoC.
- C. 22.2 J/kgoC.
- D. 11.7 J/kgoC.
Explanation
Q = mcΔTWhere: * Q = Thermal energy transferred (in Joules, J) * m = Mass of the substance (in kilograms, kg) * c = Specific heat capacity of the substance (in J/kg°C) * ΔT = Change in temperature (in °C)2. Extract Given Values from the Problem: * Mass of water (m) = 0.5 kg * Thermal energy (Q) = 1000 J * Initial temperature = 80°C * Final temperature = 90°C3. Calculate the Change in Temperature (ΔT):ΔT = Final temperature - Initial temperatureΔT = 90°C - 80°CΔT = 10°C4. Calculate the Specific Heat (c):Rearrange the formula to solve for c:c = Q / (mΔT)c = 1000 J / (0.5 kg * 10°C)c = 1000 J / 5 kg°Cc = 200 J/kg°C
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About Molar Specific Heat of a Gas
Molar specific heat is the heat required to raise the temperature of one mole of a gas by one kelvin, expressed through Q = nCΔT. Questions compare the constant volume value Cv with the constant pressure value Cp, apply the ideal gas relation Cp − Cv = R, and identify how the thermodynamic process affects heat capacity.
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