Asked in MDCAT Test Series 50 — WavesModerate

In a periodic wave, the distance between second and fifth crests is 15 cm, what is the wavelength of the wave?

Correct answer: B. 5 cm

  • A. 45 cm
  • B. 5 cm
  • C. 1/5 cm
  • D. 1/3 cm

Explanation

The following is the solution:Wavelength can be defined as the distance between successive crests. The distance between the 2nd and 5th crests is 15cm. This means that there are 3 successive crests involved. From 2nd to 3rd crest there's one wavelength, from 3rd to 4th crest there is 2nd wavelength and from 4th to 5th crest there is 3rd wavelength.Therefore, 3x = 15 where x is the wavelengthand x = 5cm

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About Waves

Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.

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