Asked in MDCAT Test Series 50 — WavesModerate

What is the wavelength of the wave if the phase angle between two points of the medium is 3 Pi/4, and are separated through a distance of 3 cm?

Correct answer: A. 8 cm

  • A. 8 cm
  • B. 9 cm
  • C. 1 cm
  • D. 12 cm

Explanation

The phase difference between two points on a wave is given by: Δφ = 2πΔd/λ where Δd is the distance between the two points and λ is the wavelength. In this case, we are given that the phase angle is 3π/4 and the distance between the points is 3 cm. So, we can plug these values into the equation above and solve for the wavelength: 3π/4 = 2π(3 cm)/λ λ = 8 cm Therefore, the wavelength of the wave is 8 cm.

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About Waves

Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.

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