In a double-slit experiment, the second-order maximum occurs at θ = 0.25°. The wavelength is 650 nm. Determine the slit separation:
Correct answer: A. 0.30 mm
- A. 0.30 mm
- B. 0.30 cm
- C. 0.30 nm
- D. 0.30 m
Explanation
The explanation is given below:In a double slit experiment, the position of the mth order maximum can be determined using the formula:d × sin(θ) = m × λ,In this case, we are given that the second-order maximum occurs at θ = 0.25° and λ = 650 nm. We need to find the slit separation, d.Plugging the given values into the formula, we have:d × sin(0.25°) = 2 × (650 nm),sin(0.25°) = sin(0.00436 radians) ≈ 0.0043594.So, we haved * 0.0043594 = 2 * 650 nm,d ≈ (2 * 650 nm) / 0.0043594,d ≈ 1300 nm / 0.0043594,d ≈ 298,015 nm.Converting nm to mm, we get:d ≈ 0.298015 mm.Rounding to two decimal places, the slit separation is approximately 0.30 mm, which corresponds to option A.
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