In 2008, Zinah earned 14% more than in 2007, and in 2009 Zinah earned 4% more than in 2008. If Zinah earned y times as much in 2009 as in 2007, what is the value of y?
Correct answer: D. 1.1856
- A. 0.5600
- B. 1.0056
- C. 1.1800
- D. 1.1856
Explanation
Choice D is correct. It's given that in 2008 Zinah earned 14% more than in 2007. Let h represent the amount Zinah earned in 2007 and let j represent the amount that Zinah earned in 2008. This situation can be represented by the equation j = (1 + 14/100)h, or j =1.14 h. It's also given that in 2009 Zinah earned 4% more than in 2008. Let k represent the amount Zinah earned in 2009. This situation can be represented by the equation k = (1 + 4/100)j, or k = 1.04j. Substituting 1.14h for j in the equation k =1.04 j yields k = (1.04)(1.14h), or k =1.1856 h. If Zinah earned y times as much in 2009 as in 2007, then the value of y is 1.1856.
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