If we move down the electrochemical series:
Correct answer: A. Reduction potential will increase
- A. Reduction potential will increase
- B. Reduction potential will decrease
- C. Oxidizing ability increase
- D. None of them
Explanation
Moving down the electrochemical series, the reduction potential will increase. The electrochemical series, also known as the activity series, is a list of elements or compounds arranged in order of their reduction potentials. Reduction potential is a measure of the tendency of a species to gain electrons and undergo reduction in a redox reaction. In the electrochemical series, elements or compounds higher up in the series have more negative reduction potentials, indicating a lower tendency to gain electrons and be reduced. Conversely, elements or compounds lower down in the series have more positive reduction potentials, indicating a greater tendency to gain electrons and be reduced. As you move down the electrochemical series, the reduction potential increase because the species are mire likely to accept electrons and be reduced. This is due to factors such as increasing atomic size, decreasing electronegativity, and decreasing ionization energy as you move down the series. In summary, as you move down the electrochemical series, the reduction potential increase, indicating an increasing tendency to undergo reduction.
Last updated
About Electrochemistry
Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
Practise Electrochemistry
696 free Electrochemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
10-2 mole of Fe3O4 is treated with excess KI solution in presence of dilute H2SO4, the products are Fe2+ and I2(g). What volume of 0.1 (M) Na2S2O3 will be needed to reduce the liberated I2(g)?
+3 and +5 oxidation states are often shown by:
3 faraday of electricity is passed through molten Al2O3 , aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of:
5.3 gm of M2CO3 is dissolved in 150 ml of 1N HCl. The unused acid required 100 ml of 0.5N NaOH. Hence equivalent weight of M is:
8H++ MnO4- → Mn2+ + 4H2O , which one is correct about given equation?