If the radius of first Bohr orbit is x, then de-Broglie wavelength in the third Bohr orbit is nearly:
Correct answer: B. 6 𝜋 x
- A. 2 𝜋 x
- B. 6 𝜋 x
- C. 9 x
- D. x / 3
Explanation
The radius of the first Bohr orbit is x, then the de-Broglie wavelength of electrons in the 3rd orbit is near:λ=3×2πx=6 πx (n=3)
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About Spectrum of Hydrogen
The hydrogen spectrum consists of discrete emission lines produced when electrons fall between quantised energy levels and release photons. Questions use the Rydberg equation, photon energy and wavelength, and identify the Lyman, Balmer, Paschen, Brackett and Pfund series, which differ from continuous spectra.
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