If the pressure on 100 c.c. of air is halved, then its volume (at the same temperature) would be ______________ c.c?
Correct answer: D. 200
- A. 100
- B. 50
- C. 205
- D. 200
Explanation
At constant temperature, Boyle's law gives P1V1 = P2V2. Halving the pressure therefore doubles the volume: 100 × 2 = 200 cc.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Engineering Thermodynamics
598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Engineering Thermodynamics questions
The internal energy of a gas obeying P (V - b) RT (where, b is a positive constant and has a constant Cv), depends upon its________________?
Which of the following equations is obtained on combining 1st and 2nd law of thermodynamics, for a system of constant mass ?
In polytropic process (PVn = constant), if n = 1; it means a/an ______________ process?
All gases above its inversion temperature, in a throttling process will show__________________?
With increase in temperature, the internal energy of a substance___________________?
(∂H/∂T)P is the mathematical expression for____________________?