If the potential difference across the two plates of a parallel plate capacitor is doubled, then the energy stored in the capacitor would be:
Correct answer: C. Four times
- A. Remains same
- B. Two times
- C. Four times
- D. Three times
Explanation
C is correct.Energy = CV2/2E∝ V2E' ∝ (2V)2E' ∝ 4V2E' ∝ 4 (V2)E' ∝ 4 E
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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