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For static electric field:

Correct answer: A. Vx E=0

  • A. Vx E=0
  • B. V.E=0
  • C. (VxE)xE=0
  • D. V.|E|2=0

Explanation

Option A is correct since under static conditions, the tangential component of the electric field is always zero on the surface and the normal component is equal to surface charge density on the conductor divided by the permittivity of space. The symbol flipped triangle represents small lengths d/dt. So the cross product of small lengths and E gives you the tangential component of electric field strength. So that must be zero.Option B is incorrect since it does not give the correct formula. Option C is incorrect since it does not give the correct formula. Option D is incorrect since it does not give the correct formula.

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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.

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