If the length of simple pendulum is increased to 6 times and g reduces to 3 times, then time period will be?
Correct answer: A. increased by √18 times
- A. increased by √18 times
- B. increased by √16 times
- C. Decreased by √18 times
- D. Decreased by √16 times
Explanation
The time period of a simple pendulum is given by: T = 2π√(L/g)where:T is the time periodL is the length of the pendulumg is the acceleration due to gravityIf the length of the pendulum is increased to 6 times and g is reduced to 3 times, then the new time period T' will be: T' = 2π√(6L/3g) = 2π√(2L/g) = √2 * 2π√(L/g) = √2 * TTherefore, the time period is increased by √2 times, which is approximately equal to √18 times.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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