If the length of a pendulum is 4 times g, its time period will be
Correct answer: A. 4π
- A. 4π
- B. 2π
- C. π
- D. π/2
Explanation
The time period (T) of a simple pendulum is given by the formula:T = 2π√(L/g)where:L is the length of the pendulumg is the acceleration due to gravityIn this case, the length (L) is 4 times g. Substituting this into the formula:T = 2π√(4g/g)T = 2π√4T = 2π * 2T = 4π
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
Practise Waves
1,281 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Simple Harmonic Motion questions
The total energy of a pendulum is 50J. What will be its kinetic energy at the mean position?
If the length of simple pendulum is increased to 6 times and g reduces to 3 times, then time period will be?
A simple pendulum with spring constant 500n/m oscillates between two points x1 = 10cm and x2 = 15 cm. What is total mechanical energy at 10cm?
If spring constant is 2 and displacement is also 2 then sum of KE and PE?
What is the kinetic energy at the extreme position during SHM?
According to the hook's law, strain is directly proportional to stress