If the horizontal range of a projectile becomes half of its maximum possible horizontal range, the probable angle of projection is:

Correct answer: A. 15 degrees

  • A. 15 degrees
  • B. 30 degrees
  • C. 45 degrees
  • D. 60 degrees

Explanation

Range is proportional to sin of twice the angle and is greatest at 45 degrees, where sin 90 equals 1, so half the maximum range needs sin 2 theta equal to 0.5, giving 2 theta equal to 30 degrees and theta equal to 15 degrees. The other solution is 75 degrees, since the two angles are complementary. Answering 30 degrees comes from halving the angle instead of the sine.

This question appeared on the UHS MDCAT 2025 paper, which you can sit online with every answer explained.

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About Projectile Motion

Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.

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