A projectile launched at angle theta has its maximum range when theta equals
- A. 30 degrees
- B. 45 degrees
- C. 60 degrees
- D. 90 degrees
Explanation
Range is proportional to sin 2 theta, which is maximum when 2 theta is 90 degrees, that is at 45 degrees, assuming level ground and no air resistance. Angles of 30 and 60 degrees give the same range as each other, since their doubles are supplementary. At 90 degrees the projectile goes straight up and the range is zero.
Related questions
For a projectile launched from level ground, the maximum range is obtained at a launch angle of
At the highest point of the path of a projectile, its velocity is
For a projectile in flight, neglecting air resistance, the horizontal component of velocity
If the horizontal range of a projectile becomes half of its maximum possible horizontal range, the probable angle of projection is:
A ball is thrown into the air with certain velocity v making an angle with horizontal. If air resistance is neglected, then at maximum height its velocity is: