If the general equation for destructive interference is given by the relation Optic path difference = (m +12), where 'm' is an integer, then the first dark fringe that appears from 'm' will be equal to:
Correct answer: C. 0
- A. 23
- B. 12
- C. 0
- D. 1
Explanation
If general equation for destructive interference is given by the relation Optic path difference = (m+(1/2)), where 'm' is an integer, then first dark fringe that appears from 'm' will be equal to 0For destructive interference • m = 0 would give us the angle of the first-order dark fringe • m = 1 would give us the second-order fringe, etc. For both bright and dark fringes, the first-order fringe is the one closest to the central maximum.
This question appeared on the UHS MDCAT 2016 paper, which you can sit online with every answer explained.
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About Superposition and Interference
Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.
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