If in a Galvanic cell: The cell potential will be:
Correct answer: A. +1.10 volts
- A. +1.10 volts
- B. -0.42 volts
- C. -1.10 volts
- D. +0.42 volts
Explanation
In a Galvanic cell, the cell potential (Ecell) is calculated using the formula:Ecell = E(cathode) - E(anode)For the given reaction, the standard reduction potential of the cathode (Cu2+/Cu) is +0.34 V, and the anode (Zn2+/Zn) is -0.76 V.Substituting these values into the formula gives:Ecell = +0.34 V - (-0.76 V) = +1.10 VThe correct answer is therefore +1.10 volts, as calculated.Other options are incorrect due to misunderstanding the electrode potentials or incorrect calculations.
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Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
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